Incomplete system 3 of 10. What is a system in sports betting
Among the types of bets in bookmakers, the system is the least popular among bettors. Many people find such bets difficult. However, this is not the case. Having at hand, it is easy to calculate all the options and choose the best one.
In this article we will look at what the 3 out of 5 system is in a bookmaker’s office. Using a specific example, we will understand how it is calculated and how it differs from other types of bets.
The essence of the system 3 out of 5
Any betting system contains a certain number of singles. The first number in the name means the number of events in the express bets, and the second number of matches from which these express bets are made up. The bet amount is distributed in equal parts between express bets. For example, if a bettor bet 100 units on a 3 out of 5 system, this means that 10 units were allocated for each of the 10 express bets.
How is the system calculated in a bookmaker's office? Everything is simple here. Each express is counted separately. The winnings of the express bets played are summed up, and thus the profitability of the entire bet is determined.
The bookmaker's rules prohibit including events from the same match in the systems. This approach is also used for individual express trains, so there is nothing new here. In our case, the 3 out of 5 system means that the bet will win if at least 3 matches are predicted correctly, but to make a profit, you need to guess at least 4 out of five if the odds are less than two.
Example of system rate calculation
For simple understanding, let's give an example. We have selected five events with different odds. It doesn't matter which sports the fights were chosen from. The main thing is to pay attention to the coefficients themselves. By substituting odds into the calculator and changing the checkboxes opposite the outcome results, we can find out the amount of profit depending on which events came together and which did not:
For these quotes, there is no option in which a bettor, having guessed 3 out of 5 events, would make a profit. The maximum you can count on is a return of 57 units using this system at the bookmaker's office.
The player will receive the largest win if he does not guess the result of the match with the lowest odds. In this case, the bet calculation is as follows:
The net gain will be 125 units. If the forecast for the game with the highest odds does not work out, then the system calculation will be as follows:
The net gain is 100 units. Here's what happens if all the events come together:
The bettor's net profit will be 424.
If the bettor had simply bet 100 fiat money on an express bet from these events, his profit would have been 1,476 units. But the fact is that the probability of such an outcome is much lower than winning using this system.
It is for this reason that the chances of making a profit by playing using this method are higher than simply launching express bets in the hope of a miracle.
To make a small profit or lose the minimum amount by guessing 3 out of 5 successful games for this system, it is necessary that all odds be greater than 2.
Combinatorics is a branch of mathematics that studies questions about how many different combinations, subject to certain conditions, can be made from given objects. The basics of combinatorics are very important for estimating the probabilities of random events, because It is they that allow us to calculate the fundamentally possible number of different scenarios for the development of events.
Basic formula of combinatorics
Let there be k groups of elements, and the i-th group consists of n i elements. Let's select one element from each group. Then the total number N of ways in which such a choice can be made is determined by the relation N=n 1 *n 2 *n 3 *...*n k .
Example 1. Let us explain this rule with a simple example. Let there be two groups of elements, and the first group consists of n 1 elements, and the second - of n 2 elements. How many different pairs of elements can be made from these two groups, such that the pair contains one element from each group? Let's say we took the first element from the first group and, without changing it, went through all possible pairs, changing only the elements from the second group. There can be n 2 such pairs for this element. Then we take the second element from the first group and also make all possible pairs for it. There will also be n 2 such pairs. Since there are only n 1 elements in the first group, the total possible options will be n 1 *n 2 .
Example 2. How many three-digit even numbers can be made from the digits 0, 1, 2, 3, 4, 5, 6, if the digits can be repeated?
Solution: n 1 =6 (because you can take any number from 1, 2, 3, 4, 5, 6 as the first digit), n 2 =7 (because you can take any number from 0 as the second digit , 1, 2, 3, 4, 5, 6), n 3 =4 (since any number from 0, 2, 4, 6 can be taken as the third digit).
So, N=n 1 *n 2 *n 3 =6*7*4=168.
In the case when all groups consist of the same number of elements, i.e. n 1 =n 2 =...n k =n we can assume that each selection is made from the same group, and the element after selection is returned to the group. Then the number of all selection methods is n k . This method of selection in combinatorics is called samples with return.
Example 3. How many four-digit numbers can be made from the digits 1, 5, 6, 7, 8?
Solution. For each digit of a four-digit number there are five possibilities, which means N=5*5*5*5=5 4 =625.
Consider a set consisting of n elements. In combinatorics this set is called general population.
Number of placements of n elements by m
Definition 1. Accommodation from n elements by m in combinatorics any ordered set from m various elements selected from the population in n elements.
Example 4. Different arrangements of three elements (1, 2, 3) by two will be the sets (1, 2), (2, 1), (1, 3), (3, 1), (2, 3), (3, 2 ). Placements may differ from each other both in elements and in their order.
The number of placements in combinatorics is denoted by A n m and is calculated by the formula:
Comment: n!=1*2*3*...*n (read: “en factorial”), in addition, it is assumed that 0!=1.
Example 5. How many two-digit numbers are there in which the tens digit and the units digit are distinct and odd?
Solution: because If there are five odd digits, namely 1, 3, 5, 7, 9, then this task comes down to selecting and placing two of the five different digits in two different positions, i.e. the indicated numbers will be:
Definition 2. Combination from n elements by m in combinatorics any unordered set from m various elements selected from the population in n elements.
Example 6. For the set (1, 2, 3), the combinations are (1, 2), (1, 3), (2, 3).
Number of combinations of n elements, m each
The number of combinations is denoted by C n m and is calculated by the formula:
Example 7. In how many ways can a reader choose two books out of six available?
Solution: The number of methods is equal to the number of combinations of six books of two, i.e. equals:
Permutations of n elements
Definition 3. Permutation from n elements are called any ordered set these elements.
Example 7a. All possible permutations of a set consisting of three elements (1, 2, 3) are: (1, 2, 3), (1, 3, 2), (2, 3, 1), (2, 1, 3), ( 3, 2, 1), (3, 1, 2).
The number of different permutations of n elements is denoted by P n and is calculated by the formula P n =n!.
Example 8. In how many ways can seven books by different authors be arranged in one row on a shelf?
Solution: This problem is about the number of permutations of seven different books. There are P 7 =7!=1*2*3*4*5*6*7=5040 ways to arrange the books.
Discussion. We see that the number of possible combinations can be calculated according to different rules (permutations, combinations, placements) and the result will be different, because The calculation principle and the formulas themselves are different. Looking carefully at the definitions, you will notice that the result depends on several factors simultaneously.
Firstly, from how many elements we can combine their sets (how large is the totality of elements).
Secondly, the result depends on the size of the sets of elements we need.
Finally, it is important to know whether the order of the elements in the set is significant to us. Let us explain the last factor using the following example.
Example 9. There are 20 people present at the parent meeting. How many different options are there for the composition of the parent committee if it must include 5 people?
Solution: In this example, we are not interested in the order of names on the committee list. If, as a result, the same people turn out to be part of it, then in meaning for us this is the same option. Therefore, we can use the formula to calculate the number combinations of 20 elements 5 each.
Things will be different if each committee member is initially responsible for a specific area of work. Then, with the same list composition of the committee, there are possibly 5 within it! options permutations that matter. The number of different (both in composition and area of responsibility) options is determined in this case by the number placements of 20 elements 5 each.
Self-test tasks
1. How many three-digit even numbers can be made from the digits 0, 1, 2, 3, 4, 5, 6, if the digits can be repeated?
2. How many five-digit numbers are there that are read the same from left to right and from right to left?
3. There are ten subjects in the class and five lessons a day. In how many ways can you create a schedule for one day?
4. In how many ways can 4 delegates be selected for a conference if there are 20 people in the group?
5. In how many ways can eight different letters be placed in eight different envelopes, if only one letter is placed in each envelope?
6. A commission consisting of two mathematicians and six economists should be composed of three mathematicians and ten economists. In how many ways can this be done?
This type of sports betting called “system” is less popular among players than the most common express and single bets. This is due to the fact that many players do not always clearly understand what a betting system is, how it can be used correctly, and how many advantages and disadvantages it can give.
What is the system
The system in a bookmaker’s office is a kind of combined set of bets consisting of express bets built by the player. The system can rightly be classified as a type of “express” bet, because when using the system, several express bets are formed.
Let's repeat it again. A system in betting is when, from all the outcomes chosen by the player, several express bets are formed, and the final odds are formed separately for each express bet. The amount of the bet itself will be divided between express bets into equal parts, and in the end the result of the system will depend on the passage of each express bet, since they are all calculated separately.
System dimension
The main concept in betting on a system is system dimension . The dimension is indicated by two numbers, for example 2 out of 3, 2 out of 5, 3 out of 5, etc., where the second number means the total number of outcomes chosen by the player, and the first shows how many outcomes the player included in one express of this system. For example, if the system dimension is 3 out of 4, we see that the system contains four express bets with three outcomes, if 2 out of 5, then, accordingly, there are five express bets with two outcomes, etc.
System Features
Betting on the system, when used correctly, has certain advantages . The main advantage is that the player will make a profit or, in any case, will not go into the red if, as a result, one of the events chosen by the player ends contrary to the forecast, as would happen in an express bet. The advantage of the system over a single bet is that if you win on all outcomes, the profit will be greater. But if you compare the profit of the system and the express, then under the same conditions the potential winnings on the express will be greater.
Fixed rate systems
In some offices it is possible to create so-called"complex systems" . This is a type of bet in which you can add the outcome you are confident in to all options of the system. Options where such an outcome does not exist will be automatically excluded. This type of system can be called by different names: surety, banker, etc. The point of such a system is that the number of options in it decreases and, accordingly, the probability of winning increases.
System calculation
How are systems calculated? For example, if we took the 2 out of 3 system, this means that we will choose three events for such a bet and win if we guess the outcome in 2 out of 3 cases. The bookmaker will show us the possible winnings, that is, the maximum winning amount that we will receive only if all the events from our system play out.
Next, imagine that we are betting on home wins. We place a bet of $30, $10 for each outcome. As a result, we will have a system for three double express trains: 1. first match + second match, 2. first match + third match, 3. second match + third match. As a result, if we guess 2 outcomes out of 3, then one express bet will play, and if we guess all 3, then all three options will play.
Bottom line
If you look at the system in general terms, it can be considered as a kind of bet between a single and an express bet. As we have already said, the system is not a popular bet among players, but it cannot be said that there are any significant flaws in it.
If used correctly, the system will regularly bring good profits to the bettor. Plus, betting on the system gives the player the opportunity to try different game strategies. But it is also worth remembering that the system still carries minor risks for the player and the chances of going into the red, so no one has canceled the pre-game analysis!
The betting system is not as popular among bookmaker players as the express system. It's a more complicated calculation. In this article on the “Bookmaker Rating” we will look at what the system is, how it is calculated and how to place a bet on the system.
The system is a combined bet consisting of express bets. Unlike an ordinary express bet, the system can win even if individual selections in a combination are lost.
The main characteristic of the system is its dimension. It is written in two numbers. For example, "3 out of 4". This means that the system consists of 4 selections, which are combined into parlays of 3 selections each. That is, there will be 4 combinations, and at least 3 selections must win for the entire system to win. The bet amount is distributed equally among all possible combinations in the system.
How is the bet system calculated?
For example, let’s take the already mentioned “3 out of 4” system. Let's say you bet 1000 rubles on it and chose the following events for it:
- Chelsea will beat Atlético Madrid 2,0 ;
- PSG will beat Bayern for 2,6 ;
- Milan will beat Rijeka for 2,14 ;
- Lokomotiv will be stronger than Fastav for 1,6 .
As we have already discussed above, in the “3 out of 4” system there will be 4 express bets with 3 selections each. A bet of 1000 rubles is divided equally into 4 combinations, that is, 250 rubles for each.
Let's say we won elections No. 1, No. 3 and No. 4. This means that in our system one combination of these selections won. We calculate the payment amount:
(2.0 x 2.14 x 1.6)x 250 = 6.848 x 250 = 1,712 rubles
With a payment of 1,712 rubles, our net profit is 712 rubles. Not much, right? But if you were to put those 4 picks together in a regular parlay, the bet would lose. However, if 2 or more selections lose in our system, the bet will lose entirely. Because each of the four combinations in the system will be a loser.
Now let's see what happens if all four events win in our system:
(2.0 x 2.6 x 2.14) x 250 + (2.0 x 2.6 x 1.6) x 250 + (2.0 x 2.14 x 1.6) x 250 + (2 .6 x 2.14 x 1.6) x 250 = 11.128 x 250 + 8.32 x 250 + 6.848 x 250 + 8.902 x 250 = 2782 + 2080 + 1712 + 2225.5 = 8799.5 rubles
With a payment of 8800 rubles, our net profit will be 7800 rubles.
What would happen if you bet these 4 selections as a regular winning accumulator? We count:
(2.0 x 2.14 x 1.6 x 2.6) x 1000 = 17.805 x 1000 = 17,805 rubles
The difference is impressive. But that's the price you pay for insurance against losing individual picks in your combination bet.
What are the limitations when creating a system?
The general restrictions that bookmakers have for betting systems are almost exactly the same. The point is that in the system is prohibited from collecting duplicate and interrelated events. You won’t be able to take more than one pick from the same match, and you won’t be able to bet on the same team winning or advancing further in a playoff match. Of course, you won’t be able to take identical elections into the system either.
But the system also has a general limitation that does not apply to regular express trains. It's that the system must consist of at least 3 elections.
Some restrictions vary from bookmaker to bookmaker. Let's look at them using the example of the most popular Russian companies:
- maximum number of selections in the system: “League of Betting” and “Fonbet” – 16, “Winline” – 20;
- maximum possible winning odds: “Winline” – 5000.0. If the established threshold is exceeded, then the calculation will still be carried out according to it;
- maximum number of combinations in the system: “Betting League” – 1001;
- minimum bet amount per system: “Winline” – 100 rubles, “Fonbet” – from 50 to 1001 rubles, depending on the size of the system.
How to make a bet system?
We will assemble the system as an example on the website.
First, look at all the system size options that this bookmaker offers us and study the number of combinations in them. 
Now we go to the bookmaker’s website and click on the selections that we want to add to the system. Let's say you have your eye on events from different sports:
- Celtic to beat Anderlecht in 1.85;
- Real Madrid will beat Tottenham in 1.48;
- Salavat Yulaev will beat Dynamo for 1.96;
- “San Antonio” will leave no chance to “Oklahoma” for 3.75.
Have you chosen? We look at the right side of the screen, where all your selections are shown. Next, click on the desired bet type – express/system. Next you need to decide on the bet amount.
Another disadvantage is that the player does not know in advance the amount that he will receive in his hands if he wins the bet. You can calculate the options, but nothing more. Wherein the payout under the system may be less than the original bet amount. In other words, you will win the bet but lose some money.
The system reduces your risks, but the maximum payout for it is also lower than for an express bet from the same selections. This is exactly how bookmakers position the system. If you are tired of making single bets, want to win a lot at once on a combination of several events, but are not ready for the all-or-nothing approach, try the system. But it is absolutely clear that a professional will never place a bet if he is not sure of his advantage over the bookmaker, so the system is not compatible with playing for a plus at a distance.
In bookmaking, each system has its own integer index, for example, 2/3, 3/5, etc. The numerator of the fraction is called the size of the bet, and the denominator is its volume. Volume represents the number of outcomes selected by the player for the forecast. The dimension of the system shows how many matching outcomes are needed to win a bet.
To win the 2/3 system, it is enough for 2 outcomes out of 3 possible to match. In this case, the entire bet is divided into express bets of 2 events. In the 3/5 system, to win, you need to match 3 outcomes out of 5. Accordingly, the bet is divided into express bets of 3 events each. A similar crushing procedure applies to other systems, for example, 4/6, 5/7, etc.
The bet size is divided between express bets. In the 2/3 system there will be 3 express options, in the 3/5 system there will be 10 options, in the 4/6 system there will be 15 express options, etc. Therefore, in the first system the bet amount is divided by 3, in the second - by 10, in the third - by 15.
Example for system 2/3:
Let there be 300 rubles at stake. This amount is distributed equally between 3 possible express trains - 100 rubles each. If one of the express bets wins, the winnings will be the product of 100 rubles and the odds of that express bet. If all the system outcomes coincide, that is, all express bets are played, then the total winnings will be the sum of the winnings of all 3 express bets.
It is important to understand that in the system there is no such thing as a general coefficient. If the bet indicates outcomes with odds of 1.7, 2.5 and 4.1, then the final calculation of the total winnings will not be carried out according to the formula: 1.7 * 2.5 * 4.1 * 300 = 17.42 * 300 = 5227 rubles. The winnings will be as follows: 1.7 * 100 + 2.5 * 100 + 4.1 * 100 = 830 rubles.
There is one important point in this type of bet. You should not select outcomes with odds less than 2.0 for the system. Otherwise, it may turn out that the winning amount will be less than the size of the bet itself.
An example of such a transaction:
Let 3000 rubles bet on system 2/3. Each of the 3 express trains receives 1000 rubles. The bet includes the following odds: 1.3, 1.4, 1.6. If all outcomes match, the winnings will be: 1000 * (1.82 + 2.08 + 2.24) = 6140 rubles. But if only one express wins, then the maximum the player will receive is: 2.24 * 1000 = 2240 rubles, and in the worst cases he will receive: 1.82 * 1000 * = 1820 rubles. In any given scenario, the capper will remain at a loss.
You can select outcomes with odds from 1.8 to 1.9, but even in this case, the winning amount of one express bet will not justify the risks.
