home-Outerwear-Lottery number table 6 out of 45 expected. Secrets of forecasting in Gosloto: choosing numbers

Lottery number table 6 out of 45 expected. Secrets of forecasting in Gosloto: choosing numbers

A little about lotteries

In numerical lotteries, a single simple combination is equally probable and is “a single indivisible entity.” In other words, in the space of a complete array, all elements (mentally imagine “cubes”) have the same size, therefore, there are no priority individual combinations. It is impossible to single out “universal combinations” in the entire array that will “always” play better than others, since the lottery machine or circulation generator is equally likely! What is most striking is that even many experienced players do not understand this.

Equally probable distribution of played combinations –
simple proof #1

Let's move on to the most natural statistics in numerical lotteries - combinatorial. To do this, you need to translate all the winning combinations, for example, in the lottery 5 out of 36, into their serial number (index) in the full array. A scatter plot of the distribution of these combinations in the space of the full array can then be plotted, while respecting the interval and location in the circulation history. Each point on this graph represents a combination that actually played in the space of the full array. Since each individual combination is distributed equally likely throughout the entire array, we can divide this space into equal parts (sectors).

Let's divide the full array of 376992 combinations,
let's say - into 12 equal parts - sectors
- 31416 combinations.

All combinations actually played at the moment in the lottery 5 out of 36
(equiprobable distribution), selected sector - any


Let's count the number of matches of each sector over the last 500 draws.
On average, there will be approximately the same number of hits of a combination in any sector - 41 times.
The chance of any sector to match is 376,992/31416 = 1 time in 12 draws (average)
For 500 draws, any sector will play 500/ 12 = 41 times (average) or 4 times for 50 draws or 2 times for 25
If the combination plays in the selected sector, then the chance of the jackpot increases 12 times for one simple combination from this sector, and will be equal to 1 in 31416. If we have 10 combinations in the game, then 1 in 3141.

What is a single combination?

Let's see what a single combination is using the example of lottery 5 out of 36. There are 376,992 such combinations in this lottery. Each combination has its own serial number in the full array (index - cell).

First combination (000001) = 01-02-03-04-05 ...
Last combination (376992) = 32-33-34-35-36 = 376992 pieces

000001 _ 01-02-03-04-05
000002 _ 01-02-03-04-06
000003 _ 01-02-03-04-07
000004 _ 01-02-03-04-08
…….
…….
…….
002024 _ 01-02-07-11-30
002025 _ 01-02-07-11-31
002026 _ 01-02-07-11-32
…….
…….
174078 _ 04-21-25-32-34
174079 _ 04-21-25-32-35
…….
376992 _ 32-33-34-35-36

Absolutely any combination in the full array is no different from others in terms of the probability of a match.
To better understand this, you need to imagine 376,992 individual lottery balls, with all 376,992 combinations labeled.
It is difficult to imagine such a quantity, much less fit it into a picture; I will show only a few balls out of 376,992 pieces.

Let's do a thought experiment- let's place these balls in a huge lottery machine, which throws out only one ball with the combination indicated on this ball for each draw. We should not forget that after each draw, the dropped ball with the combination indicated on it is thrown back into the same lottery drum. Thus, for the next draw, all combinations will be in place again, and when the lottery machine starts, they will be mixed equally with everyone else.

If it is difficult to imagine the option with balls, then let’s try to imagine a huge roulette wheel, where each ball cell represents a combination. There are 376,992 such cells, since such a lined wheel also cannot fit into the picture, so for a general understanding we will draw only a tiny part with combinations - we have highlighted the initial and final ones.

Take a closer look at the picture - the “wheel” is divided into equal cells(equally probable combinations), and the ball (draw generator) can fall into any hole (cell - index), no matter how we designated these cells (even with pictures). After the draw (spin), the wheel does not decrease - all cells remain in place.

  • Note: I would like to draw your attention once again - I am writing about a whole simple single combination. For each individual combination (cell), the meaning of any even, odd, sums, intervals between numbers, repetitions, consecutive numbers, etc. is completely lost - since the combination is a single whole and denotes a cell (index) in the full array, and their huge quantity.

We can trace only individual areas of the array (sectors, ranges, groups of numbers) for the upcoming games, therefore, we will increase our chances of winning the main prize (in individual draws) tens and even hundreds of times. Depends on which sector (array, range) we guess.

Equal distribution
combinations played - simple proof No. 2

Let's take an example of 24 numbers (lottery 6 out of 45), chosen at random.

Let's calculate the probability of complete and partial coincidence based on the real circulation history in a simplified manner (a simple calculation, and quite accurate for a large number of circulations), then use the special HYPERGEOMET function, which is present in Excel spreadsheets. This is a statistical function that can be used to calculate the probability of a complete or partial match.

(click to enlarge)

2311 lottery draws 6-45 have been loaded.

1. One match showed in 128 draws
2311/128 = 1 to 18.1.
HYPERGEOMET = 1 to 16.6.

2. Two matches showed in 472 circulations
2311/472 = 1 to 4.9
HYPERGEOMET = 1 to 4.9

3. Three matches were shown in 754 circulations.
2311/754 = 1 to 3.1
HYPERGEOMET =1 to 3.02

4. Four matches were shown in 659 circulations.
2311/659 = 1 to 3.5
HYPERGEOMET = 1 to 3.6

5. Five matches were shown in 249 circulations.
2311/249 = 1 to 9.3
HYPERGEOMET = 1 to 9.12

6. Six matches were shown in 37 runs.
2311/37 = 1 to 62.5
HYPERGEOMET = 1 to 60.51

As you can see, the probability of complete and partial coincidence almost completely coincides with the calculated values. This means that the lottery generator produces combinations with equal probability. When generating or manually marking any markers, the values ​​will differ slightly, but they will be close to the theoretical ones. The more circulation history is loaded, the closer the result. Due to the fact that the circulation in the archive is catastrophically small, we use groups of numbers of sufficient length.

From the uniform (equiprobable) distribution, another conclusion follows: It doesn’t matter which numbers are included in the group of numbers - even, odd, the top of the playing field or the bottom, etc. The only thing that matters is the number of numbers in the group, on which the probability directly depends. We look at the screenshot - 18 numbers of markers are marked - random, top, even.

(click to enlarge)

There are no significant differences in the intensity of the coincidence of 5 numbers.
In other words, the circulation generator pays attention to any marked markers evenly, no matter what you “draw” on the playing field. Sometimes they “advise” to play with so-called “pieces” - this will not change anything in terms of the probability of a match - any “piece” will play with the same frequency as a “non-piece”...

Now we know for sure - any marked group of numbers, in equal numbers, has the same probability of coincidence. Why? Because it is made up of equally probable simple combinations. In this case, how can we even understand which group may be more likely to play in the coming games?

Strategic combination generators for numerical lotteries

When you realize that a particular combination is equally likely,
then some people have complete confusion - regarding common statistics :)

For example, why “even-odd” is played in the “majority” in a certain proportion, or why “sum” plays in the middle range and more. It turns out that the combinations seem to be not equally probable? This question is easy to answer, precisely after fully realizing that a single combination is equally probable. So why do combinations seem to “love to play” in certain proportions, ranges, amounts - if they are equally probable?

  • Because we “select” arrays of equally probable single combinations with this information. It is important to know here how many combinations obtained in dedicated sectors. Arrays of combinations, highlighted with statistical information - contain different quantities equally probable combinations, therefore, these arrays have different probability for a coincidence.

Let's look at the example of statistics
even, odd numbers

  • Let's try to understand one of the popular tips when choosing a combination:
    choose combinations that contain an equal number of even and odd numbers

Let's figure out why this happens. In lottery 5 out of 36, the most common odds and evens will look like this: 2 even – 3 odd, or 3 even – 2 odd. We count the number (even - odd) of all possible combinations in the lottery 5 out of 36


To better understand why a lottery machine or a draw random number generator tries to throw out such combinations of numbers in combinations, let’s turn for clarity to the roulette wheel, which is nothing more than an equally probable random number generator, unless, of course, it’s skewed :)

Let's distribute all combinations according to the even-odd criterion together, and according to the table,
Let's draw a circular graph - imagine that these are marked sectors on a roulette wheel

Mentally add the largest sectors that contain 124848 combinations together = 124848 pieces (2 even - 3 odd) + 124848 pieces (3 odd - 2 even) = 249696 combinations out of 376992 possible, or 66.23%, or the chance of these two sectors is 376992/ 249696 = 1 to 1.5 for each spin (draw) or approximately 33 numbers out of 36.

That is why, with each test (roulette spin) of a lottery machine or draw generator, combinations from this sector will tend, in most cases, to play in an odds ratio of 2-3 or 3-2.

  • In this example it plays not a separate combination– here a dedicated “huge sector” with combinations plays, in other words, we have marked approximately 33 numbers out of 36, naturally, almost always this number of numbers will “catch” all the prize money!

Why parity in combinations like 2-3 or 3-2? Everything is explained by the costs of the decimal system, which encodes the whole combination. Each individual whole (complete) combination simply represents a cell of 376,992 pieces. Recall the thought experiment with balls, in which the combination is indicated as a whole, or an example with a roulette wheel, where each combination simply designates a cell and is indivisible. But how we select the array of combinations does not matter. It’s just convenient to follow these signs (even-odd) for part of the array - the sector.

If we generate any random combinations for the same number of combinations (2,469,696 pieces), regardless of these proportions in general, then nothing will change in terms of the probability of matching the resulting array (sector) (1 to 1.5). Any equally probable random combination generator will seem to follow this advice on its own (without any filters) - What’s interesting is that no one specifically programs it this way, putting instructions (algorithm) into it to produce exactly these combinations of numbers.

Don't believe me? Check it out for yourself!

1. Look at the draw history - most odd-even combinations will be 2-3, 3-2 (5 out of 36) and 3-3 (6 out of 45).
2. Take any random number generator, combinations - generate and write down the resulting combinations, then check.

Conclusion:

  • Most likely, such advice is addressed to those who manually fill out tickets, without any software; even a simple random combination generator will follow this advice on its own.
  • This advice is of little use to us, since the sector contains two-thirds of all combinations - not in roulette, because we play for dozens, where the chance is 1 in 3.
  • This advice is suitable for lotteries that take place very rarely, although it will not help much.
  • It is more correct to try to guess sectors 1-4, 4-1, and with fairly frequent circulations 5-0, 0-5 (we are waiting for the average period)

All strategies invented by players are far from perfect, because if there was a 100% gaming system, then the number of winnings would be large, and the winnings themselves would tend to zero. Therefore, it is necessary to use several systems simultaneously, and the more, the better. The main thing here is to select (take into account) the “influence coefficient” of each strategy on the final result. All strategies described below can be tested (each separately and in various combinations) using the program.

AmountPar.

The system is quite simple; first, let’s count how many times different pairs of numbers appear. For example: Results of the first draw = 15, 17, 22, 23, 25, 33. The pairs drawn were 15-17, 15-22, 15-23, .. , 15-33, 17-22, 17-23, .. , 17-33, .., 25-33 - 15 pairs in total. Let's continue counting for the remaining circulations. As a result, we get a table with the results of the number of drops of all pairs of balls. Based on the results of 464 draws (see figure), it can be seen that the pair 6-13 appeared 5 times, the pair 10-11 appeared 18 times, and the pair 2-5 only once in 464 draws! Feel the difference! Now let's take 3 numbers, for example 3-11-18. SumPairs will be 14+11+13=38, and for three numbers 7-14-19 SumPairs = 1+3+5=9. The difference is 4 times! All that remains is to select 6 numbers with the largest sum of pairs and fill out this combination in each draw for a long time.

Creating a table and selecting 6 numbers with the highest SumPairs manually is quite tedious, especially since the results change little by little with each draw. For calculations, it is better to use a program that will help analyze the effectiveness of the game system in Gosloto 6 out of 45 “SummaPar”.

Let's look at an example of a simple analysis. Select the circulation for the forecast - 301, click the "Forecast" button. We get a list of the 50 best combinations, and immediately see the results of the 301st draw (highlighted in red). 21 pairs and 2 triplets were guessed. With costs of 50*50=2500 rubles, we are in the minus. The forecast for the 306th draw looks even sadder - only one pair was guessed. But the next draw, 307, is pleasing - 34 pairs and 12 triplets (48 out of 50 winning tickets). Even better is the 316 draw - 19 pairs, 23 threes and 5 fours! All that remains is to guess in which circulations to use the system. For this purpose, you can additionally use other systems. For example, display not 50, but up to 5000 results and select from them using additional criteria.

Ball Step.

Let's start with the definition: The pitch is the difference between the numbers of the runs in which the Ball was drawn. If the Ball is dropped in two draws in a row, then Step = 1, if through a draw, then Step = 2, etc. Now for each Ball we count how many times Step1, how many Step2, etc. were dropped. Let's summarize the results in a table. From the table (compiled for the forecast of 465 draws) it can be seen that Ball3 came up 8 times in a row, 17 times after a draw, and only 5 times after 2 draws. The working method is as follows: For each Ball, we calculate the Step that will happen if this Ball falls out and look at the table how many times the Ball fell out at this Step. We select the Balls with the highest amount. Although, take the same 465 circulation. For Ball15, Step=1 (dropped 15 times), and for Ball2, Step=3 (2 times), and Ball2 came up... Apparently, the system can be used as an auxiliary system, in conjunction with other systems. Although, for the 460th draw, using ShaguShar you can guess 31 pairs and 19 triplets...

It is more convenient to create a table for each circulation and determine the Steps using the program.

Transitions.

The easiest way to explain the “transition” is with an example: if “8” came up in a draw, and “20” in the next draw, then this is a “transition from 8 to 20” (8->20). For example, circulation No. 1= 15 17 22 23 25 33; No. 2= 19 23 24 29 44 45. Fill out the “Transitions” table: 15->19, 15->23, 15->24, ... 33->44, 33->45. There are 36 transitions in total. We take the next pair of draws No. 2 and No. 3, etc. Let's fill out the table for 300 circulations and see what happens. The transition 11->26 occurred 14 times, and the transition 11->9 only 3 times. Let's try to make a forecast of the 301st circulation based on the "Transition" table (we can't do without a program here). Out of 50 combinations, 30 pairs and 13 triplets were guessed (better than for "SumPairs"). If you use “SumPairs” and “Transitions” at the same time, you will guess fewer: 29 pairs and 8 triplets. This suggests that each system must be used with a certain “influence coefficient”, so that each system increases the overall result, and does not decrease it. Determining such “influence coefficients” is the task of future developments.

Filter Even/Odd.

Everything is simple here: Each draw can contain from 0 to 6 even Balls and resp. from 6 to 0 odd. We put a check mark against the desired number of even Balls and only such combinations will participate in the forecast. It should be noted that the real distribution of the number of even Balls exactly coincides with the theoretical distribution, so this filter does not provide any particular advantage.

Filter "Snowflake".

An interesting filter found on the Internet. The main idea is this: based on the results of the previous draw, we divide all 45 Balls into two unequal parts - the larger part (BC) and the smaller part (MC). The number and values ​​of Balls in warheads and warheads change all the time (maximum warheads = 23 and warheads = 22, minimum warheads = 44, warheads = 1). Let's see how many Balls in the next draw ended up in the larger part and how many in the smaller part. The BC/MC ratio can be from 0/6 to 6/0. From the statistics for 300 circulations it can be seen that the BC/MC ratio was 4/2 in 32% of circulations, 3/3 in 26%, 5/1 in 22%, i.e. in 80% of circulations the ratio was 4/2, 3/3 and 5/1. The ratio 0/6 (i.e. all 6 balls hit the smaller part) happened only once (circulation 295, Mch = 19), although the smaller part often happens = 15..22 balls.

Now let's talk about how the "Snowflake" filter is calculated.
We arrange all 45 Balls in a circle, mark the Balls of the last draw and connect them with straight lines. We find the center of gravity (CG) of the resulting hexagon, connect the CG to the origin point and draw a secant perpendicularly. The secant divides all the Balls into two parts - Bch (the one with more Balls) and Mch. The results of the next draw will give us the Bch/Mch ratio. According to statistics, in 80% of draws, the majority of draws end up with 3-5 Balls, and the minority, respectively. 3-1.

Ivan Ognev's system.

Ivan Ognev's gaming system is based on the assumption that for each draw it is possible to calculate the "Characteristic Number of Ognev" (HARCHO), based on it, create a series of several numbers, one of which is likely to appear in the next draw. Ognev's numbers are calculated based on the results of the circulation as follows. For example, take circulation No. 299 = 10, 29, 31, 34, 39, 40. Find the difference between neighboring numbers = 19, 2, 3, 5, 1. Repeat the operation until one number remains (= 17, 1, 2 , 4; = 16, 1, 2; = 15, 1; = 14). The number 14 is KharCHO. Often, the last number turns out to be 0 or 1. Then, in the penultimate step, we calculate not the difference of the two numbers, but their sum. Circulation No. 300 = 8, 15, 16, 31, 38, 45. Last pair = 2, 2; Because 2-2=0, then we accept HarCHO=2+2=4. If the sum of the last pair is again equal to 1 or 0, then we leave it that way. Real KharCHO were found from 0 to 40 (in circulation No. 354, 20-20=0, next 20+20=40). Next, from KharCHO we obtain a series of numbers as follows: KharCHO is squared, cubed, etc. (we discard numbers greater than 45). We successively subtract HarCHO from the square until we get zero. Examples: KharCHO=2, row= 2, 4, 8, 16, 32; KharCHO=3, row= 3, 6, 9, 27; KharCHO=14, row=14, 28, 42;

Now let’s analyze Ognev’s numbers using the GosLotoWin program (Menu->Analysis->Ognev). The figure shows the results of the draws, a series of Ognev Numbers for each draw, and the numbers that appeared in the subsequent draw are highlighted in blue. For each draw there are from 0 to 6 numbers (usually 4-5), one or two win. Out of 430 past draws, the Characteristic Number of Ognev (HARCHO) fell out in 200 (46.5%), i.e. in every second draw one of Ognev's numbers from the previous draw falls out.

The figure shows that the most common drops are HarCHO =2(18%), =3(18%), =4(13%). Because KharCHO does not win in every draw, so it is interesting to trace the trend over a certain period of time. An example of a small sequence (1- dropped, .- didn’t drop). =.11.111.1..11..11...111..=

A small example: according to statistics, KharCHO=2 came up in 18% of draws (95 times out of the past 519), of which in 54% of cases not a single number from Ognev’s series (2, 4, 8, 16, 32) won. More often than others, Ball 16 (16%) wins, less often 4 (4%), in 5% of draws two or more Ognev numbers win at once.

You can read more interestingly about Ivan Ognev’s system.

These formulas are almost the same.
Npr- number of the draw in which the Ball is expected to appear.
N- the number of the draw in which the Ball was drawn for the last time.
m- the total number of Ball drops.
An example of the Balls forecast using the Karnauch and Power function formulas for draw No. 526. The table shows: Ball; The number of the draw in which this Ball should appear; Deviation from the predicted circulation; Deviation is the same, only for clarity, shown from the range -1..+2. The Balls drawn in Draw No. 526 are highlighted in red.
It is clearly seen that Ball 3, according to calculations using both formulas, should have fallen out in draw No. 526, and it did. The winning of Ball 5 was predicted only by the Carnauch formula, and the predicted Balls 28, 29 and 30 never came out.


Groups and Markov Chains.

Description of Groups and Markov Chains will be ready later. A brief description is in the HELP for the program GosLotoWin.

Descriptions of other systems will be added soon. If you have interesting ideas, then I will add them to the program for analysis.

Getting a draw table for any Gosloto 6 out of 45 draw on the Lottopeda lottery portal is as easy as checking your ticket. Just enter the number of the circulation you are interested in in the form on this page and click the “Get circulation table” button. The result will immediately be displayed under the form - the numbers of the balls drawn in this draw.

Why might you need the Gosloto 6 out of 45 draw tables? They can be useful in different cases. For example, in this way experienced players can check a ticket - simply compare the winning combination of the draw with the combination on your ticket and determine the number of matching numbers. If there are two or more than two, the ticket is a winner. Draw tables are also useful if you collect statistics on numbers being drawn to determine which ones are drawn more often, which ones are drawn less often, and by how much.

What data is contained in circulation tables?

You no longer need to look through multiple pages of results; all results are collected in one place. All information about draws comes directly from the Stoloto lottery company, so the draw tables do not contain errors. If you are busy developing your own system for playing Gosloto 6 out of 45 (based on the most frequently drawn numbers or, conversely, on the most rarely drawn numbers, it doesn’t matter), such a function as obtaining circulation tables will certainly make your work easier.

“Gosloto 6 out of 45” is the first state lottery. Carrying out bets in real time allows you to instantly enter ticket data into the database. Thus, after the drawing, the participant can immediately find out his winnings. The jackpot amount is constantly increasing and amounts to hundreds of millions of rubles. For clarity, look at the Gosloto 6 out of 45 archive and the results of the latest draw.

This simple game formula is attracting more and more fans. The main lotto jackpot is more than 50 million rubles. Such large cash prizes are awarded with a minimum bet value of 100 rubles. And to get a super prize you need to guess 6 numbers. Simple rules will please every player.

How to check a lottery ticket?

On the LottoAzart website you can check your Gosloto ticket using the “6 out of 45” system, watch news and tips on how to win the lottery. Participants have 2 options for checking winnings: count the number of matching numbers and look at the cash prize in the draw table; enter the ticket number in the form and the result will be shown automatically.

Biggest win

The amount of the record super prize in the entire history of the lotto was 358,358,466 rubles. A player from Novosibirsk has become an absolute multimillionaire. The cosmic jackpot was won in 1,885 in the 2016 draw.

Time will tell whether the record will be broken this year. At the moment, the mark of 50,000,000 rubles has been reached. We wish good luck and big wins to all players.

Many gambling fans often wonder how to win the lottery. Here are some tricks for the 6 out of 45 lottery. How to win it by matching the maximum number of numbers? The probability of simply guessing all 6 numbers is 1 in 8145060. As you can see, this is almost impossible. But there are several simple ways to choose the necessary numbers and get, although not the maximum, a win.

Tricks of playing the lottery 6 of 45

  • Write down all the drawn numbers from the last 8 - 10 draws and find those that come up the maximum number of times. By choosing the same numbers, you will increase the probability of your winnings.
  • Write down in advance on a blank sheet of paper the numbers that you want to cross out and only after that pick up the ticket to fill out. By choosing combinations right on the ticket itself, you will be guided by a visual picture, and not by your sixth sense and intuition.
  • As statistics show, you can win both using your personal “system” and “at random”. But in any case, it is worth considering this feature that combinations of numbers, as a rule, are not repeated, especially for the last 2 - 3 games. Also, you almost never get 2 or 3 numbers in a row; more often you end up with a discrepancy.
  • All 45 numbers can be divided into 3 groups: from 1 to 15, from 15 to 30 and from 30 to 45. And select the maximum number or most of the numbers from one group. Some circulations fit exactly this way. Alternatively, you can select most of the numbers in one of these groups, and scatter the rest among the remaining numbers.

It is important before starting the game to decide on the amount that you are willing to spend without compromising the family budget. You need to be prepared to lose it, so as not to worry in the future if you fail. Only in this case will you be able to relax and enjoy the game.



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